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Is a discrete probability distribution, involving a series of dependant trials, with more than one type of success or failure. Involves a number of n draws from a limited population, without replacement. Phrases such as "not replaced" and "not put back" hint at hypergeometric distribution to be required. The sum of xP(x) is expected outcome.
Bernoulli trials are independent of one another and all have the same probability, whereas hypergeometric trials are dependant and have varying probabilities. Bernoulli trials have only one type of success and one type of failure, whereas hypergeometric trials have more than one type of success and more than one1 type of failure.
The formula of a hypergeometric distribution is given by:
where:x1= # of successful trials of type a
x2= # of successful trials of type b
x3= # of successful trials of type c
a= total possible # of elements in type a trial
b= total possible # of elements in type b trial
c= total possible # of elements in type c trial
n= total # of trials = x1+x2+x3
What is the probability of a Formula 1 race finishing with; 2 Ferrari, 2 Renault, and 1 Honda in the top 5 if each team has 5 cars in the race and the race consists of only those teams?
let x1 = # of successful trials of type a= # of times Ferrari finishes in the top 5let x2 = # of successful trials of type b
= 2 Ferrari's= # of times Renault finishes in the top 5let x3 = # of successful trials of type c
= 2 Renault's
= # of times Honda finishes in the top 5let a = total possible # of elements in type a trial
= 1 Honda= # of Ferrari's in the race
= 5
let b = total possible # of elements in type b trial= # of Renault's in the race
= 5
let c = total possible # of elements in type c trial= # of Honda's in the race
= 5
n= total # of trials = x1+x2+x3 = 5= 0.1665
Therefore, probability of this happening is 0.1665.Example 2
There are five bananas and seven oranges in the refrigerator. Four fruits are chosen at random to serve guest. What is the probability that exactly two of the fruits will be oranges?![]()
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a=# of Oranges
=7
b=# of Bananas
=5
n=# of trials(# of fruits to be chosen)
=4
x=# of successful trials(# of oranges require)
=2
The expected values of a hypergeometric distribution can be given by:
where:X= number of successes
s= total # of items in a population which would be seen as a success
f= total # of items in a population which would be seen as a failure
n= # of trials
A jar of jellybeans contains 20 yellow jellybeans and 25 red jellybeans. If 5 jellybeans were drawn from the jar randomly, what is the expected number of red jellybeans drawn?
let n = 5
let s = 25
let f = 20
There are five bananas and seven oranges in the refrigerator. Four fruits are chosen at random to serve guest. What is the expected number of oranges chosen?References
a=# of Oranges
=7
b=# of Bananas
=5
n=# of trials(# of fruits to be chosen)
=4
Therefore, you can expect 2.3 oranges.
Jimin |
Latest page update: made by Jimin
, Jun 5 2007, 9:59 PM EDT
(about this update
About This Update
Jimin Kim and Bryan Chang Group
- Jimin
110 words added 1 word deleted 23 images added view changes - complete history) |
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Keyword tags:
Bernoulli
dependent
discrete
distribution
hypergeometric
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| Started By | Thread Subject | Replies | Last Post | ||
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| Shirleyy | Shirley, Raeshel and Marta | 0 | Jun 6 2007, 1:37 AM EDT by Shirleyy | ||
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Thread started: Jun 6 2007, 1:37 AM EDT
Watch
Your wiki is done very well. It is easy to follow and understand with descriptive steps and explanations. The picture of the fruits were also pretty neat :)
However, the equations for example 2 were a little bit blurry. Other than that, good job guys! |
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| Mr._D'Onofrio | is this page still under construction? | 1 | Jan 15 2007, 10:32 PM EST by n_amodan | ||
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Thread started: Jan 15 2007, 12:15 AM EST
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You have written at the top of the page that it's still under construction.
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| aberadamus | ... | 0 | Jan 10 2007, 7:30 PM EST by aberadamus | ||
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Thread started: Jan 10 2007, 7:30 PM EST
Watch
everything is clear but next time try to include a few more examples
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