7.4 Hypergeometric DistributionThis is a featured page

1

Hypergeometric Distribution

Is a discrete probability distribution, involving a series of dependant trials, with more than one type of success or failure. Involves a number of n draws from a limited population, without replacement. Phrases such as "not replaced" and "not put back" hint at hypergeometric distribution to be required. The sum of xP(x) is expected outcome.

Hypergeometric Trials vs. Bernoulli Trials

Bernoulli trials are independent of one another and all have the same probability, whereas hypergeometric trials are dependant and have varying probabilities. Bernoulli trials have only one type of success and one type of failure, whereas hypergeometric trials have more than one type of success and more than one1 type of failure.

Formula

The formula of a hypergeometric distribution is given by:

7.4 Hypergeometric Distribution - MDM4U1@FMG

where:
x1= # of successful trials of type a
x2= # of successful trials of type b
x3= # of successful trials of type c
a= total possible # of elements in type a trial
b= total possible # of elements in type b trial
c= total possible # of elements in type c trial
n= total # of trials = x1+x2+x3


Example 1
What is the probability of a Formula 1 race finishing with; 2 Ferrari, 2 Renault, and 1 Honda in the top 5 if each team has 5 cars in the race and the race consists of only those teams?

let x1 = # of successful trials of type a
= # of times Ferrari finishes in the top 5
= 2 Ferrari's

let x2 = # of successful trials of type b
= # of times Renault finishes in the top 5
= 2 Renault's

let x3 = # of successful trials of type c
= # of times Honda finishes in the top 5
= 1 Honda

let a = total possible # of elements in type a trial
= # of Ferrari's in the race
= 5

let b = total possible # of elements in type b trial
= # of Renault's in the race
= 5

let c = total possible # of elements in type c trial
= # of Honda's in the race
= 5

n= total # of trials = x1+x2+x3 = 5

7.4 Hypergeometric Distribution - MDM4U1@FMG
= 0.1665

Therefore, probability of this happening is 0.1665.
Example 2
There are five bananas and seven oranges in the refrigerator. Four fruits are chosen at random to serve guest. What is the probability that exactly two of the fruits will be oranges?
7.4 Hypergeometric Distribution - MDM4U1@FMG7.4 Hypergeometric Distribution - MDM4U1@FMG7.4 Hypergeometric Distribution - MDM4U1@FMG 7.4 Hypergeometric Distribution - MDM4U1@FMG7.4 Hypergeometric Distribution - MDM4U1@FMG7.4 Hypergeometric Distribution - MDM4U1@FMG 7.4 Hypergeometric Distribution - MDM4U1@FMG
7.4 Hypergeometric Distribution - MDM4U1@FMG7.4 Hypergeometric Distribution - MDM4U1@FMG 7.4 Hypergeometric Distribution - MDM4U1@FMG7.4 Hypergeometric Distribution - MDM4U1@FMG7.4 Hypergeometric Distribution - MDM4U1@FMG


7.4 Hypergeometric Distribution - MDM4U1@FMG

7.4 Hypergeometric Distribution - MDM4U1@FMG7.4 Hypergeometric Distribution - MDM4U1@FMG7.4 Hypergeometric Distribution - MDM4U1@FMG7.4 Hypergeometric Distribution - MDM4U1@FMG

a=# of Oranges
=7

b=# of Bananas
=5

n=# of trials(# of fruits to be chosen)
=4

x=# of successful trials(# of oranges require)
=2

7.4 Hypergeometric Distribution - MDM4U1@FMG
7.4 Hypergeometric Distribution - MDM4U1@FMG
7.4 Hypergeometric Distribution - MDM4U1@FMG


Expected Values of Hypergeometric Distribution

The expected values of a hypergeometric distribution can be given by:

7.4 Hypergeometric Distribution - MDM4U1@FMG

where:
X= number of successes
s= total # of items in a population which would be seen as a success
f= total # of items in a population which would be seen as a failure
n= # of trials



Example 2

A jar of jellybeans contains 20 yellow jellybeans and 25 red jellybeans. If 5 jellybeans were drawn from the jar randomly, what is the expected number of red jellybeans drawn?

let n = 5
let s = 25
let f = 207.4 Hypergeometric Distribution - MDM4U1@FMG
















Therefore, if you were to withdraw 5 jellybeans you would expect 3 to be red.


Example 2
There are five bananas and seven oranges in the refrigerator. Four fruits are chosen at random to serve guest. What is the expected number of oranges chosen?

a=# of Oranges
=7

b=# of Bananas
=5

n=# of trials(# of fruits to be chosen)
=4

7.4 Hypergeometric Distribution - MDM4U1@FMG
7.4 Hypergeometric Distribution - MDM4U1@FMG

7.4 Hypergeometric Distribution - MDM4U1@FMG
Therefore, you can expect 2.3 oranges.
References
Wgman, Diane. Mathematics of Data Management. Toronto: McGraw-Hill Ryerson, 2002.



No user avatar
Jimin
Latest page update: made by Jimin , Jun 5 2007, 9:59 PM EDT (about this update About This Update Jimin Jimin Kim and Bryan Chang Group - Jimin

110 words added
1 word deleted
23 images added

view changes

- complete history)
More Info: links to this page
Started By Thread Subject Replies Last Post
Shirleyy Shirley, Raeshel and Marta 0 Jun 6 2007, 1:37 AM EDT by Shirleyy
Thread started: Jun 6 2007, 1:37 AM EDT  Watch
Your wiki is done very well. It is easy to follow and understand with descriptive steps and explanations. The picture of the fruits were also pretty neat :)
However, the equations for example 2 were a little bit blurry.
Other than that, good job guys!
Do you find this valuable?    
Keyword tags: None (edit keyword tags)
Mr._D'Onofrio is this page still under construction? 1 Jan 15 2007, 10:32 PM EST by n_amodan
Thread started: Jan 15 2007, 12:15 AM EST  Watch
You have written at the top of the page that it's still under construction.
0  out of 1 found this valuable. Do you?    
Keyword tags: None (edit keyword tags)
Show Last Reply
aberadamus ... 0 Jan 10 2007, 7:30 PM EST by aberadamus
Thread started: Jan 10 2007, 7:30 PM EST  Watch
everything is clear but next time try to include a few more examples
1  out of 1 found this valuable. Do you?    
Keyword tags: None (edit keyword tags)

Anonymous  (Get credit for your thread)


Showing 3 of 5 threads for this page - view all