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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 11:46 PM EDT |
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can be summarized in this flow chart:This is a video of some of the permutations for a Rubik cube that lead to the solution of the cube.References: Mathematics of Data Management , Grade 12, (MDM4U). McGraw-Hill Ryersonhttp://www.youtube.com http://www.gliffy.com http://www.imeem.com
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 11:42 PM EDT |
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 11:32 PM EDT |
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finding the number of permutations -can be summarized in this Flowflow Chart:chart:This is a video of some of the permutations for a Rubik cube that lead to the solution of the cube.References: Mathematics of Data Management , Grade 12, (MDM4U). McGraw-Hill Ryersonhttp://www.youtube.com http://www.gliffy.com
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 10:05 PM EDT |
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(ACP): (4.1 Organized Counting)Therefore, there are a total 210 distinct permutations. Process of finding permutations - Flowchart:This is a video of some rubik cube permutations that lead to the solution of the cube.References: Mathematics of Data Management , Grade 12, (MDM4U). McGraw-Hill Ryersonhttp://www.youtube.com http://www.gliffy.com
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 9:59 PM EDT |
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(ACP): (4.1 Organized Counting)Therefore, there are a total 210 distinct permutations. Process of finding permutations - Flowchart:This is a video of some rubik cube permutations that lead to the solution of the cube.References: Mathematics of Data Management , Grade 12, (MDM4U). McGraw-Hill Ryersonhttp://www.youtube.com
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 9:56 PM EDT |
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Additive Counting Principle (ACP):Therefore, there are a total 210 distinct permutations. Process of finding permutations-permutations - Flowchart:This is a video of some rubik cube permutations that lead to the solution of the cube.References: Mathematics of Data Management , Grade 12, (MDM4U). McGraw-Hill Ryersonhttp://www.youtube.com
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 9:56 PM EDT |
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the Additive Counting Principle (ACP):Therefore, there are a total 210 distinct permutations. Process of finding permutations- Flowchart:This is a video of some rubik cube permutations that lead to the solution of the cube.References: Mathematics of Data Management , Grade 12, (MDM4U). McGraw-Hill Ryersonhttp://www.youtube.com
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 9:51 PM EDT |
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First digit is 1 and last digit is 2.Now use the Additive Counting Principle (ACP):(ACP):Therefore, there are a total 210 distinct permutations. Process of finding permutations- Flowchart:This is a video of some rubik cube permutations that lead to the solution of the cube. References:
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 9:49 PM EDT |
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Total # of permutations = Case 1+ Case 2+ Case 3+ Case 4 = 30 + 60 + 60 + 60 = 210Therefore, there are a total 210 distinct permutations. Process of finding permutations- Flowchart: This is a video of some rubik cube permutations that
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 9:39 PM EDT |
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last digit is 2. Now use the Additive Counting Principle (ACP): Total # of permutations = Case 1+ Case 2+ Case 3+ Case 4 = 30 + 60 + 60 + 60 = 210Therefore, there are a total 210 distinct permutations. Process of finding permutations- Flowchart:
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 9:26 PM EDT |
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and last digit is 6. (1) (6) Case 2: First digit is 2 and last digit is 6.Case 3: First digit is 2 and last digit is 2.Case 4: First digit is 1 and last digit is 2. Process of finding permutations- Flowchart:
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 9:08 PM EDT |
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How many 7-digit even numbers less than 3,000,000 can be formed using the following digits: 1, 2, 2, 3, 5, 5, 6? This questions involves cases:Case 1: First digit is 1 and last digit is 6. Case 2: First digit is 2 and last digit is 6.Case
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 9:00 PM EDT |
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How many distinct permutations can be made from the name AJAY?The name Ajay,AJAY, has a total number of permutations of 4!.These are not distinct permutations, the permutations of the identical letters (elements), “a”,“A”, does not affect the total number of distinct permutations possible.Therefore, the
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 8:50 PM EDT |
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1:1: theThe name Ajay, has a total number of permutations of 4!.These are not distinct permutations, the permutations of the identical letters (elements), “a”, does not affect the total number of distinct permutations possible.Therefore, the number of distinct permutations for Ajay does not equal 4!
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 8:41 PM EDT |
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total number of permutations for the arrangement of the six balls is 6!, but these are not distinct permutations. The distinction between the three blue
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 8:19 PM EDT |
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 8:13 PM EDT |
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These are not distinct permutations, the permutations of the identical letters (elements), “a”, does not affect the total number of distinct permutations possible.Therefore, the number of distinct permutations for Ajay does not equal 4!To Eliminate the non-distinct permutations, the total number
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 8:09 PM EDT |
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 8:05 PM EDT |
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P(n,r) = n! (n-r)! Example: What is the total number of arrangements for the following six balls if only three balls must be used? These two types were demonstrated in the previous lesson. (4.2 Factorials and Permutations)c) Permutations involving some identical elements; n! a!b!c!... Example: What is
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4.3 Permutations with Some Identical Elements
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Apr 26 2007, 7:47 PM EDT |
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